8x^2+4x=4x(2x-0)

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Solution for 8x^2+4x=4x(2x-0) equation: 



8x^2+4x=4x(2x-0)

We move all terms to the left:

8x^2+4x-(4x(2x-0))=0

We add all the numbers together, and all the variables

8x^2+4x-(4x(+2x))=0



We calculate terms in parentheses: -(4x(+2x)), so:

4x(+2x)

We multiply parentheses

8x^2

Back to the equation:

-(8x^2)



determiningTheFunctionDomain
8x^2-8x^2+4x=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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